In a box there are 6 blue ball, x red balls & 10 green balls. Probability of choosing one red ball from the given box is 1/3, then find the sum of red and blue balls in the box?
Answers
Answered by
0
Answer:
Probability of selecting red balls= Number of red balls÷Total number of balls
Probability of choosing red balls= 1÷3
Total number of balls= 6+10+x
Number of red balls=x
1÷3= x+(16+2x)
16+2x=3x
x=16
Therefore number of red balls =16
Sum of red and blue balls=16+6=22 balls
Answered by
2
Answer:
Step-by-step explanation:
Attachments:
Similar questions