Question

In a box there are 8 red,7blue n 6 green balls .One ball is picked up randomly.What is the probability that is neither red nor green

Answer 1

Answer:

red +green+blue=8+7+6=21

red +green =8+6=14

21-14=7

p(E)=7/21=1/3

Answer 2

answer:

1/3

Step-by-step explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green

= event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E)/n(S) = 7/21 = 1/3.