Question

in a bucket and balls race a bucket is placed at the starting point which ​

Answer 1

Answer:

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Answer 2

Total distance from first ball = 5m

Distance competitor has run run to pick up first ball = 2 × 5 = 10m

Distance to pickup second ball = 2 × (5+3) = 16

in this AP :-

A = 10m

n = 10

d = A1 - A2

d = 10-6 = 6

Sum of AP = Sn =

$\frac{n}{2} (2a \: + \: (n + 1)d)$

10/2 × (2 × 10 + 9 × 6)

5 × 74

370m ANS.