Question

in a bus 40% of the passengers were women. The bus carried 80 passengers 12 of them being children. How many men were left in the bus?

Answer 1

Step-by-step explanation:

total no. of men = 18

total no . of women = 40/80*100

= 50

total no . of passengers = 80

no. of women + children + men = 80

let no . of men be x

50+12+x=80

62+x =80

x=80-62

x= 18

no . of men = 18

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Answer 2

Answer:

There are 18 men passengers in the bus

Step-by-step explanation:

Given that-

A bus carry 80 passengers.

Numbers of women = 40% of 80

                                 =  $\dfrac{40 \times100}{80}$

                                 = $\dfrac{100}{2}$

                                 = 50  

Numbers of women = 50

Numbers of children = 12

Total passengers = 80

Number of men = ?

Number of men + number of women + number of children = 80

x + 50 + 12 = 80

x + 62 = 80

x = 80 - 62

x = 18

Hence, there are 18 men passengers in the bus.