Question

In a bus there were 40 passengers. The tickets were of Rs 3 and Rs 10 and total collection was Rs 255. Find out the number of passengers who cut Rs 3 tickets.​

Answer 1

let rs 3 tickets be x and 10 be y

ATQ

3x + 10y = 255. x+y=40

(1) (2)

from2

x= 40-y

(3)

substituing 3 in 1

120 - 3y + 10 y =255

120 +7y= 255

7y = 135

y =

Answer 2

There are 40 passengers in bus ,some with rs.3 tickets and remaining with rs.10 tickets.the total collection from these passengers is rs.295. find how many passengers have tickets worth rs.3

Answer:

The number passenger who cut Rs 3 ticket is 15

Step-by-step explanation:

let

The number of passenger who took ticket of 3 Rs is x

The number of passenger who took ticket of 10 Rs is y

hence Number of passengers $x+y=40$

Total collection $295=3\times x+10 \times y$

From above two equation, we get

$x=40-y$

$295=3\times x+10 \times y\\295=3\times (40-y)+10 \times y\\295=120-3y+10y\\7y=175\\y=25$

$x=40-25\\x=15$

The number passenger who cut Rs 3 ticket is 15