in A.C. circuit , the current and voltage are given by i= 5 cos wt and v = 200 sin wt respectively. power loss in the circuit is-
A. 20W
B.40W
C.1000W
D.Zero
Answers
Answered by
94
A/C to question,
i = 5cosωt
i = 5sin(ωt + π/2) [ we know , sin(90+A) = cosA ]
V = 200sinωt
V = 200sin(ωt + 0)
hence, phase difference between I and V is
Φ = π/2 - 0 = π/2
now, Power loss in circuit = Vi.cosΦ
where V and I are sinusoids rms values, Φ is the phase difference between Voltage and current.
because Φ = π/2 => cosΦ = 0
so, Power loss in circuit = 0
i = 5cosωt
i = 5sin(ωt + π/2) [ we know , sin(90+A) = cosA ]
V = 200sinωt
V = 200sin(ωt + 0)
hence, phase difference between I and V is
Φ = π/2 - 0 = π/2
now, Power loss in circuit = Vi.cosΦ
where V and I are sinusoids rms values, Φ is the phase difference between Voltage and current.
because Φ = π/2 => cosΦ = 0
so, Power loss in circuit = 0
Answered by
3
Answer: D: Zero.
Explanation:
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