Question

In a Callender's compensated constant pressure air thermometer, the volume of the bulb is 1800 cc. When the bulb is kept immersed in a vessel, 200 cc of mercury has to be poured out. Calculate the temperature of the vessel.

Answer 1

The temperature of the vessel is $T^{\prime}=307.125 \mathrm{K}$

Explanation:

Step 1:

Given,

Volume of bulb $\mathrm{V}=1800 \mathrm{cc}$

Volume of mercury poured out $\mathrm{V}_{0}=200 \mathrm{cc}$

Temperature of ice bath $\mathrm{T}_{0}=273 \mathrm{K}$

Let Temperature of vessel is represented as T ’

Step 2:

By using the formula

$\mathrm{T}^{\prime}=\frac{V}{V-V_{0}} \times T_{0}$

$\mathrm{T}^{\prime}=\frac{\text {Volume of bulb}}{\text {Volume of bulb-volume of mercury poured out }} \times \text { temperature of ice bath }$  

Step 3:

By substituting the values of given variables we get

$\mathrm{T}^{\prime}=\frac{1800 \times 273}{1800-200}$

$T_{=}^{\prime}=\frac{9 \times 273}{8}$

By calculating above values the obtained temperature is  

$T^{\prime}=307.125 \mathrm{K}$

Answer 2

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307.125 K

hope it help