Question

In a car race on straight road, car a takes a time t less than car b at the finish and passes finishing point with a speed 'v' more than that of car

b. Both the cars start from rest and travel with constant acceleration a1 and a2 respectively. Then 'v' is equal to

Answer 1

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According to Question♢
In a car race car a takes time t less than car b and passes the finishing line with a velocity v more than car b if both the car starts from rest then and assuming that it travel with acceleration a1 and a2 then prove that v=t root of a1 &a2
A)
For A
acceleration=a1
total time=t'-t
final velocity=u+v

For B
acceleration=a2
total time=t'
final velocity=u

s=(1/2)a1(t'-t)^2=(1/2)a2(t')^2
therfor
1)(1-t/t')=(a2/a1)^(1/2)
also
(u+v)^2=2a1s
(u)^2=2a2s
dividing both we get
2)(1+v/u)=(a1/a2)^(1/2)
but u=a2t'
so substitute this value in 2 and put value of t' from 1
therefore we get
v=t(a1a2)^(1/2)
v=t root of a1 a2

Answer 2

Explanation:

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