Question

In a carius determination of 0.234 grams of organic substances gave 0.334 of barium sulphate then calculate the weight percentage of sulphur in given compound​

Answer 1

Given :

▪ Weight of organic substance = 0.234g

▪ Weight of barium sulphate = 0.334g

To Find :

▪ Weight percentage of sulphur in given organic compound.

Formula :

▪ Atomic weight of sulphur = 32g/mol

▪ Molecular weight of barium sulphate = 233g/mol

$\bigstar\:\underline{\boxed{\bf{\pink{\%S=\dfrac{32}{233}\times \dfrac{W_{BaSO_4}}{W_{org}\times 100}}}}}$

Calculation :

$\dashrightarrow\sf\:\%S=\dfrac{32}{233}\times \dfrac{0.334\times 100}{0.234}\\ \\ \dashrightarrow\sf\:\%S=0.137\times 142.7\\ \\ \dashrightarrow\underline{\boxed{\bf{\gray{\%S=19.55\%}}}}$

Imp. Formulas of Carius method :

↗Quantitative analysis of Chlorine :

$\bigstar\:\boxed{\bf{\red{\%Cl=\dfrac{35.5}{143.5}\times \dfrac{W_{AgCl}}{W_{org}}\times 100}}}$

↗Quantitative analysis of Bromine :

$\bigstar\:\boxed{\bf{\blue{\%Br=\dfrac{80}{188}\times \dfrac{W_{AgBr}}{W_{org}}\times 100}}}$

↗Quantitative analysis of Iodine :

$\bigstar\:\boxed{\bf{\green{\%I=\dfrac{127}{235}\times \dfrac{W_{AgI}}{W_{org}}\times 100}}}$

↗Quantitative analysis of Phosphrous :

$\bigstar\:\boxed{\bf{\purple{\%P=\dfrac{62}{222}\times \dfrac{W_{Mg_2P_2O_7}}{W_{org}}\times 100}}}$

Answer 2

In the above Question , we have the following information -

In a carius determination of 0.234 grams of organic substances gave 0.334 of barium sulphate .

To find -

calculate the weight percentage of sulphur in given compound.

Solution -

Here , we can write the following equation -

$\sf{ Organic \: Compound \longrightarrow BaSO_{4} + ... }$

So , we can observe that -

1 mole of the organic compound produces 1 mole of BaSO4

Now ,

Molar Mass of BaSO 4

=> 137 + 32 + ( 16 × 4 )

=> 233

Molar Mass of Sulphur

=> 33

Hence ,

1 gram of BaSO 4 will produce the mole fraction of ( 33 / 233 ) g Sulphur .

Now , we have -

No of grams of BaSO4 is 0.334

So ,

No of grams of Sulphur

=> ( 33 / 233 ) × 0.334 gram Sulphur

=> 0.0458 grams of Sulphur .

Now , total mass of the compound is given as -

=> 0.234 grams .

Hence ,

Percentage of Sulphur

=> ( 0.0458 / 0.234 ) × 100 %

=> 19.6 percent approximately .

__________________