Question

In a Carnot engine, temperature of the source is 500 K and that of the sink is 375 K. If the engine absorbs 600 kcal heat from the source per cycle, find (i) its efficiency (ii) work done per cycle (iii) heat released in the sink. (J = 4.2 J/cal)

Answer 1

Explanation:

i efficiency = 1- (375/500) = 25 %

ii work done = efficiency*heat absorbed

= 0.25*600 = 150 kcal = 630 kJ

iii heat released in sink

= heat absorbed - work done

= 600 - 150 = 450 kcal = 1890 kJ