Question

In a carton there are 15 rectangular cards of which 7 are green and rest are white, 18 pentagonal cards of which 3 are green and rest are white. One card is selected at random from the carton. Find the probability that selected card is:

(a) a rectangle

(b) a pentagon

(c) a pentagon of green colour

(d) a rectangle of white colour​

Answer 1

Answer:

a) 15 / 33

b) 18 / 33

c) 3 / 33

d) 8 / 33

Answer 2

(a) probability (rectangle ) = $\frac{15}{33}$

(b)probability ( pentagon) =  $\frac{18}{33}$

(c)probability ( a pentagon of green colour ) =  $\frac{3}{33}$

(d)probability ( a rectangle of white colour​ ) =  $\frac{8}{33}$

Step-by-step explanation:

number of rectangular cards = 15

number of pentagonal cards = 18

total number of cards = 33

rectangular green color cards= 7

rectangular white color cards= 15 - 7 = 8

pentagonal green color cards = 3

pentagonal white color cards = 18-3 = 15

probability = $\frac{number of outcomes}{total number of outcomes}$

(a) probability (rectangle ) = $\frac{15}{33}$

(b)probability ( pentagon) =  $\frac{18}{33}$

(c)probability ( a pentagon of green colour ) =  $\frac{3}{33}$

(d)probability ( a rectangle of white colour​ ) =  $\frac{8}{33}$

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