l can't solve this questions help me
Attachments:
Answers
Answered by
1
.Let the no. of red balls be xprobability that the ball drawn is not red=(18-x)/18probability that the ball drawn is red = x/18Now, if two more red balls are added then,probability of getting a red ball = (x+2)/18.................(1)According to the
question,probability of getting a red ball =(9/8)(x/18)..............(2)From equation 1 and 2(x+2)/18=(9/8)(x/2)(x+2)/18=x/1616x+32=18x2x=32x=16Therefore, the no. of red balls is 16.And the probability of not getting a red ball in the first case = (18-16)/18=2/18=1/9
hope it help u
mark me brainliest
question,probability of getting a red ball =(9/8)(x/18)..............(2)From equation 1 and 2(x+2)/18=(9/8)(x/2)(x+2)/18=x/1616x+32=18x2x=32x=16Therefore, the no. of red balls is 16.And the probability of not getting a red ball in the first case = (18-16)/18=2/18=1/9
hope it help u
mark me brainliest
Similar questions