Math, asked by bajpaiatharva4936, 2 months ago

In a certain Algebra 2 class of 26 students, 16 of them play basketball and 9 of them play baseball. There are 5 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?

Answers

Answered by pulakmath007
2

SOLUTION

GIVEN

In a certain Algebra 2 class of 26 students, 16 of them play basketball and 9 of them play baseball. There are 5 students who play both sports.

TO DETERMINE

The probability that a student chosen randomly from the class plays basketball or baseball

EVALUATION

Here it is given that total number of students = 26

So total number of possible outcomes = 26

Let A be the event that a student play basketball and B be the event that a student play baseball

Then A ∪ B is the event that the a student plays basketball or baseball

Then

n(A) = 16 , n(B) = 9 , n( A ∩ B ) = 5

Now

n( A ∪ B )

= n(A) + n(B) - n( A ∩ B )

= 16 + 9 - 5

= 20

Hence the required probability

 \displaystyle\sf{ =  \frac{Number \:  of  \: favourable  \: cases \:  for  \: the \: event }{Total \:  number \:  of \:  possible \:  outcomes } }

 \displaystyle\sf{ =  \frac{20}{26} }

 \displaystyle\sf{ =  \frac{10}{13} }

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