Question

.In a certain city 125 men in a sample of 500 were found to be smokers. In another city the number of smokers was 375 in a random sample of 1000.Does this indicate that there is a greater population of smokers in the second city than in the first?​

Answer 1

Answer:

Yes, Second city has more smokers than First City

Step-by-step explanation:

If we take the percentage of smokers:

Percentage of smokers in city A

$\frac{125}{500} \times 100 = 25\%$

Percentage of Smokers in city B

$\frac{375}{1000} \times 100 = 37.5\%$

Since, Smokers in City B > Smokers in City A

Smokers in city B are greater.

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Answer 2

Required Answer:-

For comparing two different datas, we can use Arithmetical elements such as ratio, percentage. I am using percentage for easier explanation$.$

City 1:-

• No. of smokers = 125
• Total no. of men = 500

Then, % of smokers:

= No. of smokers / Total no. of men × 100

= 125 / 500 × 100

= 1 / 4 × 100

= 25 %

City 2:-

• No. of smokers = 375
• Total no. of men = 1000

Then, % of smokers:

= No. of smokers / Total no. of men × 100

= 375 / 1000 × 100

= 37.5 %

Hence:-

The percentage of smokers in second day i.e. 37.5% is more than the percentage of smokers in first day i.e. 25%.

• Smokers of 2nd > Smokers of 1st

Thus, Our assumption is true.