Question

in a certain city 60 percent read newspaper A, 40 percent read newspaper b 0 percent read newspaper c 20 percent read A and b 30 percent read a and c 10 percent read b and c the percentage of people who don't read any of these newspaper is

Answer 1

Answer:

15

Step-by-step explanation:

100-18=42+68+51-30-28

Answer 2

The given

in a certain city 60 percent read newspaper A, 40 percent read newspaper b 0 percent read newspaper c 20 percent read A and b 30 percent read a and c 10 percent read b and c

we have to find the percentage of people who don't read any of these newspaper is question is

It is found by the formula 100- people who reads atleast any one of the news paper.

P(A) =60

P(B)=40

P(C)=0

P(AnB)=20

P(AnC)=30

P(BnC)=10

P(AnBnC) =0

The formula for finding the probability of people who reads the newspaper.

P(AUBUC) = P(A) +P(B) +P(C) -P(AnB) -P(AnC) -P(BnC) +P(AnBnC)

substituting the obtained values in the above formula we get. ddd

$x = 60 + 40 + 0 - 20 - 30 - 10 + 0$

no body reads the newspaper c and nobody reads all the three newspaper.

thus, the value on that place is 0.

$x = 100 - 60 = 40$

P(AUBUC) =40.

we have to find the no. of people who does not reads the newspaper.

it is obtained by 100 - P(AUBUC).

The total probability value will be taken as 1 , here it is taken as 100 because of a percentage.

The total percentage is 100.

$100 - 40 = 60$

60% of the people does not reads any of the newapaper

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