Question

In a certain code language 'A' is coded as '2Z6', 'P' is coded as '1K1' and 'T' is coded as '0G7'. Now answer the following question. The code for 'MAN' is

Answer 1

1N42Z61M3

Explanation:

The above is instance of "coding and decoding aptitude". In this , the "coding & decoding"  is one's capability of "deciphering" the rule & "breaking the code" to decipher the message which would  be tested.

Given, that "A" is coded as "2Z6", "P" is coded as "1K1" and "T" is coded as "0G7".

This means, the alphabet in each of this code (2Z6, 1K1, & 0G7 represent the same number place when these alphabets are written in reverse order.

1. That is, if A is the first  alphabet in the normal order then Z is the first alphabet in reverse order
2. If P is the 11th alphabet from reverse, then K is the 11th alphabet from normal order
3. If T is the 7th alphabet from reverse order, then G is the 7the alphabet from normal order.

Similarly the numbers before and after the middle alphabet for 2Z6, 1K1, & 0G7, represents the number place of the middle alphabet in regular order

1. 2Z6 = 26th alphabet which is Z
2. 1K1 = 11th alphabet  which is K
3. 0G7 = 7th alphabet which is 7

Therefore, from the above  the code for MAN would be

• M = 1N4 (M and N are 13th alphabets in regular & reverse order respectively and N is the 14 the alphabet in regular order)
• A = 2Z6 - already explained above
• N = 1M3 (N & M are 13th alphabets in reverse & regular order respectively and M is the 13th alphabet in regular order)

Thus the code is 1N42Z61M3

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