Question

In a certain double slit experimental
arrangement interference fringes of width
1.0 mm each are observed when light of
wavelength 5000 Å is used. Keeping the set
up unaltered, if the source is replaced by
another source of wavelength 6000 Å, the
fringe width will be :-

1) 0.5 mm
2) 1.0 mm
3)1.2 mm
4) 1.5 mm
​

Answer 1

Answer:

it will be 1.2mm

because of wavelength

Answer 2

Answer:

Option C is the correct answer...

we know that,

The relation between the wavelength and fringe width is as follows.....

fringe width=n×lambda×D/d

from this we conclude that fringe width is directly proportional to the wavelength...

fringe width 1/fringe width 2=wavelength 1/wavelength 2

5000/6000=1.0mm/x

x=1.2mm

So the next fringe width is 1.2mm

Explanation:

Hope it helps you....