Question

In a certain oscillatory system, the amplitude of motion is 5m & the time taken is 4s. The time taken by the particle for passing between points which are at distance of 4m & 2m from the center & on the same side of it will be

Answer 1

Amplitude A = 5As the time period of the oscillatory system is 4 s, its frequency will be 1/4 Hz and the angular frequency will be ω = 2π/4The displacement of the particular executing oscillatory motion system at any instant is given as x =  A sin ωtLet at time t1 & t2 the particular reaches position 2m and 4m from centre.2 = 5 sin 2π/4 t14 = 5 sin 2π/4 t2Calculate t1 and t2.  The difference t = t2 - t1 is the time taken by the particular to pass through the given points

Answer 2

This is the correct answer