Question

in a certain rase there three boys A,B,C the wining probablity of A is twice than B and wining probablity of B is twice than C .if P(A) + p(B)+P(C)=1 then find the probablity of each boy​

Answer 1

Answer:

Answer is given in picture

Answer 2

Answer:

$p(a) = \frac{4}{7}$

$p(b) = \frac{6}{21}$

$p(c) = \frac{1}{7}$

Step-by-step explanation:

P(A) + P(B) + P(C) = 1 - equa.1 According to the conditions Apply it on equa.1 . You have capability to do it try it it's quite easy for you & for me.