Question

In a certain stats class,the marks obtained by student on a class test followed a normal distribution with mean of 68% & standards deviation of 10%.What is the probablit that the mean test mark from a sample of 25 students from the class was mote than 72%?​

Answer 1

Answer:

t(70) = (70-68)/[10/sqrt(25)] = 1

P(x-bar > 70) = P(t > 1 when df = 24) = 0.1636

Step-by-step explanation:

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