Question

In a chemical reaction,10g sodium sulphate react with 15g barium chloride and give 17g of sodium chloride and barium sulphate. Calculate the amount of barium sulphate formed in the reaction.​

Answer 1

The above mentions about a chemical reaction between Sodium sulphate and barium chloride which gives sodium chloride and barium chloride as product.

In a balanced chemical equation, law of conservation of mass is strictly followed. It means mass of substances in reactant side = mass of substances in product side$.$

Given,

• Sodium sulphate = 10 g
• Barium chloride = 15 g
• Sodium chloride = 17 g

We have to determine for Barium sulphate in the reac.

According to law of conservation of mass,

➝ Mass of Na2SO4 + Mass of BaCl2 ➝ Mass of NaCl + Mass of BaSO4

➝ 10 g + 15 g = 17 g + Mass of BaSO4

➝ Mass of BaSO4 = 25 g - 17 g

➝ Mass of BaSO4 = 18 g (Answer)

Tip:

We should always balance a reaction to satisfy the law of conservation of mass. This is more accurate and precise.

Answer 2

Answer:

this is a chemical reaction i will explain it easily dot worry

Explanation:When sodium sulphate solution reacts with barium chloride solution results in double displacement reaction in which ions are exchanged.

Na  

2

​  

SO  

4

​  

+BaCl  

2

​  

⟶2NaCl+BaSO  

4

​  

 

In this reaction barium sulphate and sodium chloride are formed,the solution in water consists only sodium chloride because sodium chloride dissolves in water while barium sulphate it settles down and a white precipitate is formed (insoluble).✔i hope this equation will be helpful plz mark as brainlist