In a chemical reaction ,13 g of silver nitrate combines with 27 g of sodium chloride. 30 g of silver chloride is precipitated. Calculate the amount of sodium nitrate formed:
Answers
Answered by
0
Answer:
the amount of NaNO3 formed is 17.85g or 0.21 mole.
Explanation:
to calculate this first see the balance chemical equation
AgNO3 + NaCl ----------> AgCl + NaNO3
the no. of mole of AgCl formed is equal to no. of mole of NaNO3 formed.
the 30g of AgCl contains 0.21 mole, so the number of moles of NaNO3 formed are also 0.21. so we can calculate the mass of NaNO3 from the number of moles. and that is 17.85g.
the question is somehow not clear.
Similar questions