Question

in a chemistry lab two beakers A and B contains 62% and 84% of spirit respectively.if two liters from A is mixed with 4 liters of B.The ratio of sprit and water in the resulting mixture is.​

Answer 1

Answer:

The resulting mixture is 76.67%

Step-by-step explanation:

i.) 2 liters of A

ii.) 4 liters of B

iii) total of 6 liters

iv) (2$\times$0.62) + (4$\times$0.84) = 6 $\times$ x

    therefore 1.24 + 3.36 = 6x

           x  = 4.6/6  = 76.67%

Answer 2

Given :

• In a chemistry lab two beakers A and B contains 62% and 84% of spirit respectively. If two litres from A is mixed with 4 litres of B.

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Find :

• The ratio of sprit and water in the resulting mixture is.

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Calculations :

→ A = 0.62 × 2

→ A = 1.24 liters

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→ B = 0.84 × 4

→ B = 1.68 liters

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Sum of their mixture:

→ A2 + B4 = AB6 liters

→ 0.24 + 1.68

→ 1.92 liters

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→ Sum of mixtures = 6 - 1.92

→ Sum of mixtures = 4.08

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As per the given question, we have to find their ratio:

→ Ratio = 1.92 : 4.08

→ Ratio = 8 : 17

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Therefore ,

• The ratio of sprit and water in the resulting mixture is 8:17 .