Question

In a children park an inclined plane is constructed with an angle of incline 45° in the middle part . Find the acceleration of a boy sliding on it if the friction coefficient between the cloth of the boy and the incline is 0.6 and g=10 m/s²

Answer 1

the acceleration will be 15m/s

Answer 2

Let mass of boy be m.  

Normal force on the boy = Component of weight perpendicular to the plane

= mgCos45°

Frictional force on the boy by the surface =µmgCos45°

Component of weight along the plane = mgsin45°  

Net force on the boy down the incline = Mg.sin45°- µMg.cos45°  

ma = mg(1/√2-0.6/√2)

a = (0.4/√2)g  

a = 0.283 × 10

∴ a = 2.83 m/s².

Hope it helps.