in a Chimp Zoo there are 1 billion monkeys. The probability that a monkey in the zoo has seen a Banyan tree is 0.6. The probabilty that a monkey has seen a mango tree is 0.65. What is the minimum percentage of monkeys in the zoo who have seen both the trees?
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we know that p(a)=0.6
and p(b)=0.65
hence p(a+b)=p(a)×p(b)
=> 0.6×0.65=0.39
=>0.39×100
=39% ans
and p(b)=0.65
hence p(a+b)=p(a)×p(b)
=> 0.6×0.65=0.39
=>0.39×100
=39% ans
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