Question

in a circle of diameter 40cm the length of minor arc of cord?​

Answer 1

Answer:

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Answer 2

Answer:

Diameter of the circle =40 cm

∴ Radius (r) of the circle =40/2=20 cm

Let AB be a chord (length = 20 cm) of the circle.

In △OAB, OA = OB = Radius of circle = 20 cm

Also, AB = 20 cm

Thus, △OAB is an equilateral triangle.

∴θ=60∘=π/3πradian

We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ=l/r

∴π/3=arc AB/20⟹arc AB=20/3π cm

Step-by-step explanation:

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