Question

in a circle of radiaus item find the distance of the chord of length 3cm form the contse​

Answer 1

Given :-

the radius of the circle = 17 cm

length of the chord = 16 cm

To Find:-

find the distance of the chord from the centre?

Solution:-

we know that,

• A Perpendicular drawn from the centre of the circle to the chord, bisects the chord. Hence, the point will be the midpoint of the line segment

(see the refer diagram)

here,

O is the centre

AB is chord

OB is radius

C is the midpoint of chord AB

➪ CB = AB/2

➪ CB = 16/2

➪ CB = 8 I'm

now, in right-angled triangle OBC

by Pythagoras theorem ;

(CB) ² +(OC) ² =(OB) ²

:↦8 ²+(OC) ² =17 ²

:↦64+(OC) ² =289

:↦(OC) ² =289−64

:↦(OC) ² =225

:↦OC= 225

:↦ OC=15cm

hence, the distance of the chord from the centre is 15 cm.

Answer 2

Check my answer and give me replay my answer is correct or wrong