in a circle of radius 10.5 cm of the minor arc is one-fifth of the major arc. Find the area of sector corresponding to the major arc
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radius of the circle r = 10.5 cm
and minor arc is one fifth of the major arc.
let the major arc subtend the angle θ on the circumference.
therefore minor arc subtend angle (360 - θ) on the circumference.
minor arc = 1/5* major arc
2πr*360-θ360
=15*2πr*θ3605(360-θ)
=θ1800-5θ
=θ6θ
=1800θ
=18006
=300
therefore the area of the sector corresponding to the major arc
=πr2*θ360
=227*10.5*10.5*300360
=33*10.5*56
=288.75 cm2
I hope it helps you
:)
________________________
________________________
radius of the circle r = 10.5 cm
and minor arc is one fifth of the major arc.
let the major arc subtend the angle θ on the circumference.
therefore minor arc subtend angle (360 - θ) on the circumference.
minor arc = 1/5* major arc
2πr*360-θ360
=15*2πr*θ3605(360-θ)
=θ1800-5θ
=θ6θ
=1800θ
=18006
=300
therefore the area of the sector corresponding to the major arc
=πr2*θ360
=227*10.5*10.5*300360
=33*10.5*56
=288.75 cm2
I hope it helps you
:)
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5
Answer:- The area of sector corresponding to the major arc is 288.75 square cm.
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