Question

In a circle of radius 17 cm, find the distance of a chord of length 16cm from the centre

Answer 1

Given: radius 17 cm, chord of length 16 cm

To find: The distance of a chord from the centre.

Solution:

• Now let the chord be AB and the centre be O.

• Let the perpendicular from centre to chord be M, OM.

• Now we know that perpendicular from centre to the chord bisects the chord, so AM = MB = 16/2 = 8 cm.

                  OB = 10 cm

• Now consider triangle MOB, by Pythagoras theorem, we have:

                  OB² = OM² + BM²

                  10² = OM² + 8²

                  OM² = 100 - 64

                  OM² = 36

                  OM = 6 cm

Answer:

           So the distance of a chord from the centre is 6 cm.

Answer 2

Answer:

6cm

Step-by-step explanation:

OB^2 =om^2=om^2+Bm^2

10^2=om^2+8^2

om^2=100-64

om^2=36

om=6cm

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