Question

In a circle of radius 21cm,an arc subtends an angle of 60 degree at the centre, Find
1.the length of the arc 2.area of the sector formed by the arc
3.area of the segment formed by the corresponding chord

Answer 1

Answer:

1. r=21cm

theta=60°

length of arc=2πr×theta/360°

length of arc=2×22/7×21×60°\360°

length of arc=22cm

2. r=21cm

theta=60°

area of sector = πr²×theta/360°

area of sector=22/7×21×21×60°/360°

area of sector=231cm²

3. radius of circle is equal and arc subtend at the centre is 60° . So, triangle formed in the circle is equilateral triangle.

area of equilateral triangle=√3/4×a²

area of equilateral triangle=√3/4×21×21

area of equilateral triangle=441/4×√3cm²

area of segment formed by corresponding chord=area of sector- area of triangle

area of corresponding chord=(231-441/4×√3) cm²

Answer 2

Answer:

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