In a circle of radius 3.5 cm a secant is passing through it's centre. Find the area of any of those segments formed by secant?
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Draw a circle of radius r=3.5cm
Take two points P and Q in either side of diameter AOB
From measurement it is found that ∠APB=∠AQB=90o
This states the proof of theorem: Angle made by diameter and any point on circumference is 90
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Answer:
19.25cm²
Step-by-step explanation:
the secant that passes through the centre is
its diameter so we have to find the area of a
semicircle.
radius=3.5 cm
area of semicircle=(πr²)/2
=>((22/7)x3.5x3.5)/2
=19.25cm²
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