Math, asked by BrainlyHelper, 1 year ago

In a circle of radius 6 cm, a chord of length 10 cm makes an angle of 110° at the centre of the circle. Find:
(i)the circumference of the circle
(ii)the area of the circle
(iii)the length of the arc AB,
(iv)the area of the sector OAB.

Answers

Answered by nikitasingh79
5

Answer:

The circumference of a circle is 37.71 cm , Area of a circle is 113.1 cm² , Length of an arc, AB 11.52 cm and Area of sector of a circle,AOB is  34.5 cm²  

Step-by-step explanation:

Given :

Radius of circle, r = 6 cm

Chord of a circle = 10

Angle at the centre of the circle, θ = 110°

(i) Circumference of a circle ,C = 2πr  

C = 2 × 22/7 × 6  

C = 264/7  

C = 37.71 cm

Circumference of a circle = 37.71 cm

(ii) Area of a circle,A = πr²

A = 22/7 × 6²

A = 22/7 × 36

A = 792/7  

A = 113.1 cm²

Area of a circle = 113.1 cm²

(iii) Length of an arc ,l = (θ/360) × 2πr

l = (110°/360°) × 2 × 22/7 × 6

l = 11/36 × 44/7  ×6

l = (11 × 44 ×6) / (36 × 7)

l = 484/ 6×7 = 484/42  

l = 11.52 cm

Length of an arc,AB = 11.52 cm

(iv) Area of the sector of a circle, AOB = (θ/360) × πr²

= (110°/360°) × 22/7  ×6²

= 11/36 × 22/7  × 36

= (11 × 22 ) /7  

= 242/7  

= 34.5 cm²

Area of sector of a Circle ,AOB = 34.5 cm²  

Hence, the circumference of a circle is 37.71 cm , Area of a circle is 113.1 cm² , Length of an arc, AB 11.52 cm and Area of sector of a circle,AOB is  34.5 cm²  

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Answered by Niranjan7262
1

Answer:

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