in a circle of radius 7 cm and R substance and angle of 60° at the centre find the area of sector
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Question :-
In a circle of radius 7 cm the sector subtends an angle of 60° at the centre. Find the area of the sector.
Area of a sector is given as
(∅/360) × πr²
Where, ∅ = the magnitude of angle in degrees.
Here, ∅ = 60°
r = 7 cm
So, area = (60/360) × 22/7 × 7²
= 1/6 × 22/7 × 49
= 1/6 × 154
= 77/3 cm²
= 25.67 cm² (approx)
In a circle of radius 7 cm the sector subtends an angle of 60° at the centre. Find the area of the sector.
Area of a sector is given as
(∅/360) × πr²
Where, ∅ = the magnitude of angle in degrees.
Here, ∅ = 60°
r = 7 cm
So, area = (60/360) × 22/7 × 7²
= 1/6 × 22/7 × 49
= 1/6 × 154
= 77/3 cm²
= 25.67 cm² (approx)
Answered by
7
▶ Question - In a circle of radius 7 cm, an arc subtends at angle of 60° at the centre. Find the area of sector.
▶ Given :
i) Radius of the circle ( r ) = 7 cm
ii) An arc subtends at angle of 60° ( θ )
▶ To Find :
Area of the sector
▶ We know that :
Area of sector = θ / 360 × πr^2
= 60 / 360 × 22 / 7 × 7 × 7
= 1 / 6 × 154
= 154 / 6
= 25.6 m^2
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hey iitgenius1234
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