Question

In a circle with center C and chord DE, seg CF ⊥ chord DE. If diameter of a circle is 20 cm and DE= 16 cm, then CF = ? Give reason for your answer.​

Answer 1

Answer:

Perpendicular from the centre of a circle to a chord bisects the chord

We know that OB⊥AB

From the figure we know that D is the midpoint of AB

We get

AD=BD

We also know that O is the midpoint of BC

We get

OC=OB

Consider △ABC

Using the midpoint theorem

We get OB∥AC and

OD=

2/1 ×AC

By cross multiplication

AC=2×OD

Therefore, it is proved that AC∥DO and AC=2×OD

Answer 2

Step-by-step explanation:

Please Mark second answer as the BRANIEST answer of this question