Question

In a circle with centre o, ABCD is a cyclic quadrilateral with AB as a diameter of the circle. AC and BD produced meet at E. If angle CED=70, then what is the measure of angle COD

Answer 1

Answer:

∠COD = 90°

∵ We know that diagonals of a quadrilateral intersect at mid point and since AB is diameter of the circle and AO , OB are radius of the circle.

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Answer 2

Step-by-step explanation:

AS we know triangle in a semicircle is 90' angle triangle BE and AE is straight line so