In a circle with centre o. Ad is a diameter and ac is achord b is point on ac, such that ob=5cm and angle oba=60 degree in angle doc =60 degree, then what is the length of bc
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Given, OB = 5cm, angle OBA = 60°
angle OBA is subtended by minor arc CD and the same arc subtends angle CAD on the remaining part of the circle. So, angle CAD = 30°.
By angle sum property of triangle AOB, angle BOA = 90°
By linear pair, angle OBC = 120°
By linear pair axiom, angle COB = 30°
By angle sum property of triangle BOC, angle BCO = 30°
NOW, BOC IS AN ISOSCELES TRIANGLE
SO BC = 5cm
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