In a circle with centre o, diameter AB and diameter CD
are giren and prove that AD = BC.
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Answer:
In triangle COB and triangle AOD,
AO = BO [radius of the circle]
DO = CO [radius of the circle]
angle COB = angle AOD [vertically opposite angles]
therefore triangle COB congruent to triangle AOD
AD=CB [C.P.C.T.]
(Proved)
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