in a circle with centre O, OC is perpendicular to chord AB which is equal to 24cm, if OC = 5cm than find radius of the circle
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Perpendicular drawn from centre of a circle to chord bisects the chord.
AC=BC=12cm
And ∠OCB=90°
Thus, triangle OCB is a right angled triangle
OB=13cm.
Therefore by Pythagoras theorem
OB² =OC²+BC²
OC² =OB²−BC²
OC= √13²- 12²
OC=5cm
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