Question

in a circuit 2 ohms and 3 ohms resistance are connected in parallel what is the resultant resistance in ohms​

Answer 1

Explanation:

Resistance in parallel for R1 and R2 resistors is

(R1*R2) /R1+R2

So answer is 3*2/3+2

6/5=1.2

Answer 2

Answer:

In a circuit 2 ohms and 3 ohms resistance are connected in parallel the resultant resistance is 1.2ohms​

Explanation:

• A resistor is  used to resist the current flow through  a circuit

• If two resistors with resistances $R_{1} ,R_{2}$ are connected in parallel in a circuit the effective resistance that appeared in the circuit is given by the formula

        $1/R_{eff} =1/R_{1} +1/R_{2}$

        ⇒$R_{eff} =\frac{R_{1} R_{2} }{R_{1} +R_{2} }$

from the question, we have given that

the value of resistance  $R_{1} =2$Ω

the value of the other resistance  $R_{1} =3$Ω

substitute the given values to get the effective resistance  

⇒$R_{eff} =\frac{2*3 }{2+3 }$

⇒$R_{eff} =6/5=1.2$ Ω