Question

please!!!!!! solve
for class 10​

Answer 1

Give me brainliest for the answer please

Answer 2

Answer:

768.8 km / hr   ( approx )

Step-by-step explanation:

Using right angled triangles:

tan (elevation angle) = ( height of plane ) / ( horizontal distance to plane )

=> horizontal distance to plane = height / tan(elevation angle)

So...

Initially, the horizontal distance to the plane was

= 3000 m / tan 60°

= 3000 m / √3

= 1000√3 m

6 seconds later, the distance to the plane was

= 3000 m / tan 45°

= 3000 m / 1

= 3000 m

So the plane travelled (3000 - 1000√3) m = (3-√3) km in 6 seconds.

6 seconds = 1/10 minutes = 1/600 hours

So the speed of the plane, in km / hr, is

speed = distance / time

    = (3-√3) km  /  (1/600) hr

    = 600(3-√3) km / hr

    ≈ 768.8 km / hr (approx)