Question

In a circuit a coil of resistance 2ohm then magnetic flux changes from 2wb to 10 wb in 0.2 sec .The charge flow in coil

Answer 1

Charge flow in coil will be 4C

Coil of resistance - 2ohm ( Given)

Change of flux = from 2 to 10 (Given)

The induced emf in coil (E) = change in Φₘ / t  

= (10 - 2) / 0.2  

= 40

Now we will find, E = I . r

I = 40 / 2

I = 20 Amp

I.t = q

= q = 20 x 0.2

= 4 C