Question

in a circuit having constant resistance current is increased 4 times what will be the power dissipation in such case​

Answer 1

Answer:

16 times

Explanation:

I' =4I. (given). ---------(1)

P=I^2×R

P'=I'^2×R

P'=(4I)^2×R. (FROM 1)

P'= 16I^2×R

P'= 16(I^2×R)

P' = 16P. (SINCE P=I^2×R)