Question

in a circuit shown the thermal power is dissipated in R1 is filled the
power dissipated in R2 is​

Answer 1

Answer:

$(2)\frac{4P}{9}$

Explanation:

1) Let the current in the branch containing $R_2$ and $R_3$ be $i_2$ and $i_3$ respectively.

2) According to the question ,

$P=i^2R_1=i^2R$

3) Since,  $R_2$ and $R_3$  are connected in parallel to each other.

They have, same potential difference.

By Ohm's Law,

$=>\frac{i_2}{i_3}=\frac{R_3}{R_2}=\frac{2R}{R}=2 \\ \\=>i_3=\frac{i_2}{2}$

4)  Now,

According to KCL,

$i=i_2+i_3\\ \\=i_2+\frac{i_2}{2}=\frac{3i_2}{2}=>i_2=\frac{2i}{3}$

$P_{R_2}=i_2^2R_2= (\frac{2i}{3})^2*R=\frac{4i^2R}{9} =\frac{4P}{9}$

Hence, Our Required Answer is 4P/9.

Answer 2

4P÷9 correct answer is 5his not so 6AM the 8 day 7 year sentence and I have no