Question

in a circuit the charge stored in the 4 microfarad capacitor is ​

Answer 1

Answer:

it is simple

first find equivalent capacitance

then use q=CV

this is the required charge...since charge remains same in series

hope it helps you ❤️

Answer 2

The charge stored in the 4 micro farad capacitor is 24 micro coulomb.

Explanation:

In this case, it is required to find the charge stored in the $4 \mu F$. The capacitors $4\ \mu F$ and $8\ \mu F$ are in series. Their equivalent is given by :

$\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}$

$\dfrac{1}{C}=\dfrac{1}{4}+\dfrac{1}{8}$

$C=2.67\ \mu F$

Both capacitors are connected in series, and in series combination charge remains constant. It is given by :

$q=CV$

$q=2.67\times 9$

$q=24.03\ \mu C$

or

$q=24\ \mu C$

So, the charge stored in the 4 micro farad capacitor is 24 micro coulomb.

Learn more,

Combination of capacitors

https://brainly.in/question/9610657