In a circular park of diameter 80 m there is a square shaped ground of maximum area what is area of a playground is
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Hi there!
Here's the answer :
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Let side of square = a
diameter of circle = d
Given,
square ground is in circular park.
From Pythogoras theorem
Hyp² = Opp² + Adj²
=> d² = a² + a²
=> d = √2×a
Given D = 80mts
=>√2×a= 80
To get Area of playground,
Find area of square I.e., a²
Square on Both sides
=> a² = 6400/2
=> a² = 3200 sq. mts
•°• Required area of playground = 3200 sq. mts
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Here's the answer :
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Let side of square = a
diameter of circle = d
Given,
square ground is in circular park.
From Pythogoras theorem
Hyp² = Opp² + Adj²
=> d² = a² + a²
=> d = √2×a
Given D = 80mts
=>√2×a= 80
To get Area of playground,
Find area of square I.e., a²
Square on Both sides
=> a² = 6400/2
=> a² = 3200 sq. mts
•°• Required area of playground = 3200 sq. mts
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
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