In an arrangement series of an even number of 2n terms which term is median?
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Here's the answer:
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The series of Even No.s :
2, 4, 6, ……………
Given that No. of terms = 2n
=>Total Even No. of terms exists in series
-Here there exists two mid terms as there are even No. of terms in series
Mid term = 2n/2 = n
=> Mid term is nth term and (n+1)th term
•°• nth term = 2n
(n+1)th term of series = 2(n+1)
-Find Average of these two mid terms
=
•°• Required Median = 2n+1
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
The series of Even No.s :
2, 4, 6, ……………
Given that No. of terms = 2n
=>Total Even No. of terms exists in series
-Here there exists two mid terms as there are even No. of terms in series
Mid term = 2n/2 = n
=> Mid term is nth term and (n+1)th term
•°• nth term = 2n
(n+1)th term of series = 2(n+1)
-Find Average of these two mid terms
=
•°• Required Median = 2n+1
•°•°•°•°•°<><><<><>><><>°•°•°•°•°
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