Question

in a circular table cover of radius 32cm a design is formed leaving an equilateral triangle ABC in the middle as shown in figure 12.2 4 find the area of design​

Answer 1

Step-by-step explanation:

Area of design = Area of Circle - Area of triangle

Area of circle = πr^2

=22/7 * 32 * 32

= 3218.29 cm^2

angle AOB= 120°

angle AOB= 120°value of sin 120° = √3 /2

Area of triangle AOB = 1/2 * r^2 * Sin theta

= 1/2 * 32 * 32 * √3/2

=443.41 cm^2

all three triangle formed by centre are equal

so,

area ABC = arAOB + arBOC + arCOA

= 443.41 + 443.41 + 443.41

=1330.23 cm^2

Area of design = 3218.29 - 1330.23

=1888.06 cm^2

NOTE:-If your answer doesn't match. Reverify above calculations.

Answer 2

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