Question

IN A CIRCULAR TRACK(DISTANCE 400m) an athlets runs 1/4 of the ground. so what would be the displacement.

Answer 1

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Answer 2

r= 700/11
so radius are OB and OA
SO JOIN A AND B
as 1/4 part of circle makes angle of 90°

now by using pythagoras theorem
${(ab)}^{2} = {(ao)}^{2} + {(bo)}^{2}$
ab^2= (700/11)^2+(700/11)^2
ab^2= 2(700/11)^2
ab^2=
$2 \times \frac{700}{11} \times \frac{700}{11}$
4900/121 × 2
=9800/121
= 809.9
= 810m (approx.)

so displacement = 810m


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