In a city, 40% of the people are illiterate and 60% are poor. Among the rich, 10% are illiterate. The percentage of the illiterate poor population is
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Let Total number of people (= 100\)
Total poor people = 60% of 100 => 60/100 * 100 = 60
Therefore rich people = 40% of 100 =>40/100 * 100 = 40
Total illiterate people = 40% of total people => 40/100 * 100 = 40
Among rich, 10% are illiterate = 10% of 40 =>10/100 * 40 = 4\)
Number of the illiterate poor population = 40 - 4 => 36\).
Therefore; illiterate poor = 36 total population = 100.
Required percentage =36/100 * 100 = 36%.
Total poor people = 60% of 100 => 60/100 * 100 = 60
Therefore rich people = 40% of 100 =>40/100 * 100 = 40
Total illiterate people = 40% of total people => 40/100 * 100 = 40
Among rich, 10% are illiterate = 10% of 40 =>10/100 * 40 = 4\)
Number of the illiterate poor population = 40 - 4 => 36\).
Therefore; illiterate poor = 36 total population = 100.
Required percentage =36/100 * 100 = 36%.
Answered by
11
Let Total number of people =100
Total poor people = 60% of 100
= 60/100×100 = 60
Therefore rich people =
40% of 100 = 40/100× 100 = 40
Total illiterate people = 40% of total people =40/100×100=40
Among rich, 10% are illiterate = 10% of 40 =10/100×40=4
Number of the illiterate poor population =40−4=36
Therefore; illiterate poor =36
Total population =100=
Required percentage =36/100∗100=36 answer.
Total poor people = 60% of 100
= 60/100×100 = 60
Therefore rich people =
40% of 100 = 40/100× 100 = 40
Total illiterate people = 40% of total people =40/100×100=40
Among rich, 10% are illiterate = 10% of 40 =10/100×40=4
Number of the illiterate poor population =40−4=36
Therefore; illiterate poor =36
Total population =100=
Required percentage =36/100∗100=36 answer.
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