Math, asked by anitasarkar, 1 year ago

in a city 50 percent people read newspaper A, 45 percent read newspaper B, and 25percent read neither A nor B. what percentage of people read both the newspapers A as well B?


sp2003: is it 27.5%.?? idk just s guess

Answers

Answered by nitthesh7
71
Nice question mate!!!✌✌✌

The ans is 20 percent.

Refer attachment for understanding the process.

If u find it as most helpful pls mark it as brainliest.


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Answered by RenatoMattice
44

Answer: 20% of people read both the newspaper A as well B.

Step-by-step explanation:

Since we have given that

Percentage of people read newspaper A = n(A) = 50%

Percentage of people read newspaper B = n(B) = 45%

Percentage of people read neither A nor B = n(A ∩ B)' = 25%

So, n(U) = 100%

So, it becomes,

n(A\cup B)=n(U)-n(A\cup B)'\\\\n(A\cup B)=100-25\\\\n(A\cup B)=75\%

So, Finally it becomes,

n(A\cup B)=(A)+n(B)-n(A\cap B)\\\\75=50+45-n(A\cap B)\\\\75=95-n(A\cap B)\\\\75-95=-n(A\cap B)\\\\20=n(A\cap B)

Hence, 20% of people read both the newspaper A as well B.

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